njgirl5565

Okay so this is what I have so far

<!--LOGO--> <div id="logo"> <a class="text_logo" href="<?php echo home_url(); ?>"><img src="<?php bloginfo('url'); ?>/images/jazzysteez.jpg" alt="" /></a> <h1><a class="text_logo" href="<?php echo home_url(); ?>"><?php bloginfo('name'); ?></h1> <?php if($option["scl_description"] == "1"){ ?><div class="desc"><?php bloginfo('description')?></div><?php } else { ?><?php } ?> </div>

Also, would putting the image in the https://ftp.jazzysteez.com/images/jazzysteez.jpg be okay?

When I use the new code, and keep the href=” segment from the original template, I receive this error :

Parse error: syntax error, unexpected ‘.’ in /home1/jazzyste/public_html/wp-content/themes/scylla-lite/header.php on line 67

Okay here is the link to Header.php
https://pastebin.com/gQ2TdPaz

and here is the link to my site
https://www.jazzysteez.com

Thanks so much!