cpkid2

Ok, I got some help and found the solution.

Around line 496, change this:

$nopages = "AND $wpdb->posts.post_type = 'post'";

To this:

$nopages = "AND $wpdb->posts.post_type IN ('post','videos','projects')";

With videos and projects being the custom post types.

Hope this helps someone out there.

I found that on line 496, changing post to another post type worked. So how can I add in an array of post types? I’m not much of a coder so I’m not sure how I’d put it in.

$nopages = "AND $wpdb->posts.post_type = 'projects'";

I’m incorporating the Popular Posts into a tab powered by jQuery so using a widget wouldn’t be possible (I think). Thank you for taking the time to reply, anyway.

By the way, I’m using the template tag and currently calling the function like this:

<?php if (function_exists('wpp_get_mostpopular')) wpp_get_mostpopular("limit=4&range=all&order_by=views&pages=0&thumbnail_width=23&thumbnail_height=23&thumbnail_selection=usergenerated&stats_comments=0&stats_views=1&stats_date=1&stats_date_format='M j, Y'&wpp_start=\"<ul id='popular-posts-content'>\""); ?>

I noticed that if I add pages=1 to the list of attributes, it shows everything including the posts in my custom post types and pages. However, if I use pages=0, it only shows the posts in the default post type. Is there a way to only get rid of the actual pages?

try img.wpp-thumbnail:hover

Would LOVE this feature for custom post types!!

Jeremy, I copied your altered code, named it wordpress-popular-posts.php and replaced it with the original wordpress-popular-posts.php in the plugin folder and I got “Sorry, no data found”. Is there something else I need to do?

Nevermind, I installed it again and it works. The error came out only right when I upgraded the plugin.

This would be an awesome feature. I switched to ShareThis because ShareDaddy doesn’t have a manual insert option.

Nevermind, this was a Yahoo Small Business Hosting issue. Site is back up now.

Sweet!

I changed line 32 from:

<?php if( $c < 4 ) : for ($dummy= $c; $dummy < 5; $dummy++;) : ?>

to:

<?php if( $c < 4 ) : for ($dummy= $c; $dummy < 4; $dummy++) : ?>

I removed the last semicolon and it seems to be working now. Also, I’m wondering why there was a ‘5’ in the original line instead of ‘4’? Is that necessary for the code to work or was it a mistake? It outputted 5 boxes so I changed it to 4 and it’s working now.

I get an unexpected semicolon on line 32.

Parse error: syntax error, unexpected ';', expecting ')' in blog.php on line 32

Thank you for your time, esmi. However, for some reason only one post + one dummy image post is showing.

Here is my full code: https://pastebin.com/5kVU6GMC (I changed it to query 4 posts instead of the original 6)

In the output, only one post and one dummy post shows instead of having one post and three dummy posts showing.

Any ideas?

Thanks for the tip on having the page name and post type name different.

I just have one question: If I name the post type something like “my-projects” and name the page “projects”, the link points to mysite.com/my-projects/ instead of mysite.com/projects

Anyway I can fix this?