XHTML Help! Please?
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Can anyone tell me how I could make this XHTML valid?
Thanks!
<?php
$feedUrl = "https://www.azcentral.com/rss/feeds/news.xml"; // enter your feed's url here
$feedOut = getSomeFeed($feedUrl, 5, false, "feed-azcentral", '', 36); // enter a cache name
if (!empty($feedOut))
{
start_block("AZ News", "feedread", "li");
echo $feedOut;
end_block();
}
?>
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Viewing 7 replies - 1 through 7 (of 7 total)
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