Sidebar Login – cant log out

2.7 uses a new function that outputs the logout url. Just use this code
<?php echo wp_logout_url(); ?>

Thanks for the prompt response, Do I just add that code to the anywhere into the sidebar.php file?

Whereever you would like the link to show up. You actually use the code like this.
<a href="<?php echo wp_logout_url(); ?>">Logout</a>

I have added that code into the php file.
It shows two logout buttons which is okay but when i hit the new one i get an error:

“The requested URL /< was not found on this server.”

Please forgive my ignorance..Im very new to editing plugins etc….

Where are you adding the code?

When i look through the file i see:

<li class=”page_item”>‘.__(‘Dashboard’).’
<li class=”page_item”>‘.__(‘Profile’).’
<li class=”page_item”>‘.__(‘Logout’).’

I add it just after that or in theory you could replace the last one although im probably extremely mistaken

Is that in a plugin file though. Try putting it directly in your sidebar.php file.

I put in in the sidebar.php but same thing happened
Is there anyplace in particular i need to put it?

You need to place the code in “al_template.php” in the “ajax-login” folder.

Look for this in al_template.php:
/******* This part is drawn when user IS logged in. *******/

This is where the code needs to go:
<a href="<?php echo get_settings('siteurl') . '/wp-login.php?action=logout&amp;redirect_to=' . $_SERVER['REQUEST_URI']; ?>"><?php _e('Logout'); ?></a>

So now it should look like this:
<a href="<?php echo wp_logout_url('/wp-login.php?action=logout&amp;redirect_to=' . $_SERVER['REQUEST_URI']); ?>" title="Log out">Log out</a>

Hope this helps. ??

Hi Friends,

This problem is not big problem ??

Use this codes :
‘.$usp_language[‘logout’].’

For all more webmasters ?nformation CLICK HERE

Up to here this is code : )

<a href="'.wp_logout_url(get_option('siteurl')).'" title="'.$usp_language['logout'].'" >'.$usp_language['logout'].'</a>