How to use separator for listing categories?

  • Resolved hungzai

    (@hungzai)


    8 years, 6 months ago

    At the moment it list AppleOrangeBanana etc.
    I would like to use separators to list like Apple | Orange | Banana

    <?php
foreach((get_the_category()) as $childcat) {
if (cat_is_ancestor_of(16, $childcat)) {
echo '<a href="'.get_category_link($childcat->cat_ID).'">';
 echo $childcat->cat_name . '</a>';
}}
?>

    Anyone has any idea? Thanks in advance.

Viewing 3 replies - 1 through 3 (of 3 total)

  • Hello hungzai,

    Please update your code with the below code:

    <?php
foreach((get_the_category()) as $childcat) {
if (cat_is_ancestor_of(16, $childcat)) {
echo '<a href="'.get_category_link($childcat->cat_ID).'">';
 echo $childcat->cat_name . ' | </a>';
}}
?>

    Thanks

    Thread Starter hungzai

    (@hungzai)

    Very good!! Thank you so much!!. However now there is a separator that comes up after the last category. Any idea how to remove that last separator? (sorry for the trouble!)

    Thread Starter hungzai

    (@hungzai)

    For those who are keen. Here is the solution.

    <?php $args = array('child_of' => 16,'hierarchical' => 0,
'parent' => 16,);

$terms = get_terms( 'category', $args );
if ( ! empty( $terms ) && ! is_wp_error( $terms ) ) {
	$count = count( $terms );
	$i = 0;
	$term_list = '<p class="my-category-list">';
	foreach ( $terms as $term ) {
		$i++;
		$term_list .= '<a href="' . get_term_link( $term ) . '" title="' . 

$term->name . '">' . $term->name . '</a>';
		if ( $count != $i ) {
			$term_list .= ' | ';
		}
		else {
			$term_list .= '</p>';
		}
	}
	echo $term_list;
 }
 ?>
Viewing 3 replies - 1 through 3 (of 3 total)
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