• Hi all (sorry for my bad english, but I’m italian ??

    My site has a structure like this one:

    Who?
    -Profile
    -Contact

    Services
    – Drink
    – Eat

    Products
    – Apples
    – Bananas

    I would like to print in home page a <div> for each “mother page” containing a link to each child page. How could I do it automatically in the loop?

    I tried with the function “if have_posts” but i think i need something like “if have_pages”……

    Thank you very much in advance for any suggestion!
    Zam ??

Viewing 3 replies - 1 through 3 (of 3 total)
  • <?php
    $parent_id = $posts[0]->ID;
    $args=array(
      'post_parent' => $parent_id,
      'post_type' => 'page',
      'post_status' => 'publish',
      'posts_per_page' => -1,
      'caller_get_posts'=> 1
    );
    $my_query = null;
    $my_query = new WP_Query($args);
    if( $my_query->have_posts() ) {
      echo 'List of Posts';
      while ($my_query->have_posts()) : $my_query->the_post(); ?>
        <p><a href="<?php the_permalink() ?>" rel="bookmark" title="Permanent Link to <?php the_title_attribute(); ?>"><?php the_title(); ?></a></p>
        <?php
        $meta = get_post_meta($post->ID, 'cf1', true);
        if ($meta){
          echo 'customfield1: '. $meta;
        }
      endwhile;
    }
    wp_reset_query();  // Restore global post data stomped by the_post().
    ?>
    Thread Starter zamarrone

    (@zamarrone)

    Hi MichaelH, thank you very much! Tomorrow I will try to integrate your code in my pages and i’ll let you now.

    thanks again
    zam

    Actually rereading your question, that code won’t work as it only returns the child pages of the current page.

    You’ll have to use Function_Reference/get_pages with the parent=0 argument to return the top level pages, then iterate though that array to display the parent page, then get the children of that parent page with the child_of=x argument.

Viewing 3 replies - 1 through 3 (of 3 total)
  • The topic ‘Print a list of child pages for each mother page’ is closed to new replies.