How can i call do_shortcode [yop_poll id=”1″] from theme function.php

`add_action(‘wp_ajax_get_contact_form’, ‘get_contact_form’);

function get_contact_form(){

if(isset($_GET[‘form_id’])):
echo do_shortcode(‘[contact-form-7 id=”152″ title=”Contact page”]’);
echo do_shortcode(‘[popup_anything id=”461″]’);
echo do_shortcode(‘[yop_poll id=”1″]’);
//echo do_shortcode(‘[yop_poll id=”‘.$_GET[‘form_id’].'”]’);
endif;
exit();
}

Here is my code in this contact-form-7 and popup_anything work as expected but yop_poll not working its return ‘[yop_poll id=”1″]’

Hello

This seems to be caused by the way we define the shortcodes within the plugin.
An workaround would be the code below

$yop_poll = new YOP_Poll_Public();
$yop_poll_params['id'] = $_GET['form_id'];
$yop_poll_params['tracking_id'] = '';
echo $yop_poll->generate_poll( $yop_poll_params );

This code should replace

echo do_shortcode(‘[yop_poll id=”‘.$_GET[‘form_id’].'”]’);

I hope this helps.

• This reply was modified 3 years, 6 months ago by YOP.

Thank you so much @yourownprogrammer,

Here I want to add one more point, $yop_poll = new YOP_Poll_Public(); or $yop_poll = new YOP_Poll_Pro_Public(); whatever function in you public.php.

@yourownprogrammer Need one more minor help

Your code id working fine now but when i am trying to call with show_results its not working as expected.

Like when we passing show_results parameter at that time the poll should be return result only

Here is my code.

$yop_poll = new YOP_Poll_Pro_Public();
         $yop_poll_params['id'] = $_GET['form_id'];
         $yop_poll_params['tracking_id'] = '';
         $yop_poll_params['show_results'] = $_GET['form_id'];
         echo $yop_poll->generate_poll( $yop_poll_params );

I was tried to find out some way but not able to get success. Please Help!

Thank you.

For more Clearance (i am not able to upload screenshot so i am trying my best as words)

I have load total 3 Polls which 2 polls are as questions and 1 poll is show only results (this things are working fine with mention below array)

Array ( [id] => 1 [results] => 0 [tracking_id] => [show_results] => )
Array ( [id] => 2 [results] => 0 [tracking_id] => [show_results] => )
Array ( [id] => 1 [results] => 0 [tracking_id] => [show_results] => 1)

Whenever i am going to open poll on new popup in popup i am getting this array
Array ( [id] => 1 [show_results] => 1)
but Poll loaded with question not result only.

I hope you got me what i want to explain.

Thanks

• This reply was modified 3 years, 6 months ago by khatrijay18.

Hello

You should be able to display results with this extra line

$yop_poll_params['show_results'] = '1';

I hope this helps.

@yourownprogrammer Yes of course i should, but the thing is i am loading it on popup when poll submitted. i can see the poll in popup but its asking question instead of result.

I have already added your code as mention above one of my example.

• This reply was modified 3 years, 6 months ago by khatrijay18.

@khatrijay18

Can you paste here the exact code you are currently using to display the results in the popup?

This is my script which trigger popup first and then call YOP_POLL and whatever it return it will replace in popup HTML.

jQuery('.callPopUp .popupaoc-link').trigger('click');
            jQuery.ajax({
                url: ajax_script.ajax_url, //global variable provided by WP
                type: 'GET',
                cache: false,
                data: {
                    'action' : 'get_contact_form',
                    'form_id' : getId
                },
                success: function(data){
                    console.log(data);
                    //jQuery('#content').append('hello Here : ', data);
                    jQuery('#paoc-modal-2 .paoc-popup-modal-cnt').html(data);
                }
            });

And Here is my AJAX call.
add_action(‘wp_ajax_get_contact_form’, ‘get_contact_form’);

function get_contact_form(){
if(isset($_GET[‘form_id’])):
$yop_poll = new YOP_Poll_Pro_Public();
$yop_poll_params[‘id’] = $_GET[‘form_id’];
$yop_poll_params[‘show_results’] = $_GET[‘form_id’];
echo $yop_poll->generate_poll( $yop_poll_params );
endif;
exit();
}

Thank you

Here is the updated code to use on the AJAX call

function get_contact_form(){
if(isset($_GET[‘form_id’])):
$yop_poll = new YOP_Poll_Pro_Public();
$yop_poll_params[‘id’] = $_GET[‘form_id’];
$yop_poll_params[‘show_results’] = '1';
echo $yop_poll->generate_poll( $yop_poll_params );
endif;
exit();
}

Let us know how it goes.

Hi @yourownprogrammer ,

I tried to pass static value on show_results but its doing same it return poll as question format instead of result format.

@khatrijay18

Yes, it does return the poll as question format.
Once done, a js should kick in to display the results.

Can you share a link so we can run a test?

Hello @yourownprogrammer ,

Sorry for delay, I was create demo link for you reference.

Here it is: https://54.225.8.87/test_wp/index.php/recourse/

Please check and let me know if you required anything else.

Hello @yourownprogrammer ,

Did you check the link? do you need anything else from my side? Please let me know.

Thank you.

@khatrijay18 apologies for the delay in getting back to you.

I looked at the link you sent over, run a test on both polls you have setup and in both cases I am seeing only a thank you message in the popup.

I thought it was displaying the poll?