Echo Image if Video not present
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Hi, I have been struggling with this for a while now and I know this can be done but have not been able to find a thread.
I think I need to modify this code
$value = get_field( “VIDEO” );
if( $value ) {
echo $value;
} else {
echo ‘IF VIDEO IS NOT UPLOADED THEN DISPLAY THE IMAGE THAT IS UPLOADED’;
}
So, what I am trying to do is in the same DIV on the page either display a VIDEO if there is one. If not then display the IMAGE that will be uploaded instead.
Any help will be much appreciated.Thanks,
Shaun.
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