Display an external feed as a page: parsing an RSS Feed

Good morning from Canada,

I have set up a syndicated feed list through “Rojo.com” (excellent service) and I would like to parse it to a page. I already have it working for the title and the link, however the “content/description” is formatted in an array that doesn’t seem to parse.

Here is the code:

<!-- RSS feed -->

<?php
if (is_page('RSS Syndication') ){
 require_once(ABSPATH . WPINC . '/rss.php');
 $rss = fetch_rss('https://www.server.com/externalfeed.rss');
 for( $i=0; $i<25; $i++ ) {
  $item=$rss->items[$i];
  $pubdate=substr($item['pubdate'], 0, 16);
  echo '
   <a href="'.$item['link'].'" title="'.$item['title'].'"><b>'.$item['title'].'</b></a>
   <i>'.$pubdate.'</i>
   <i>'.$item['content'].' content</i>
   <i>'.$item['summary'].' summary</i>
   <i>'.$item['title'].' title</i>
   <i>'.$item['content'].' content</i>
   <a href="'.$item['link'].'">more...</a>
   ';
  }
 }
?>
<!-- End of feed -->

First of all, the content outputs “Array”, and the summary is blank. Second, is there a built in parser in rss.php that I can use? I noticed the “get_rss” function in the bottom of the rss.php file.

Thank you for your support, I am extremely new to this.