Call Widget in php

Hi,

please, can you post me the code you use ?

I used
<?php the_widget( 'yith-woo-ajax-navigation-3', 'dropdown', 'abc' ); ?>

yith-woo-ajax-navigation-3: name got from chrome’s inspect element
‘abc’ is attribute type that I want to filter
I need dropdown filter with OR parameter

I also tried the following, but to same result:
<?php the_widget( 'yith-woo-ajax-navigation', 'dropdown', 'abc' ); ?>

Hi,

This code are wrong because the correct syntax is:

<?php the_widget( $widget, $instance, $args ); ?>

Where…

$widget is the widget class name

$instance The widget’s instance settings

$args the argument for the widget class

this is the way it works, so in your case you can:

<?php
$instance = array(
    'title' 		= "Your Widget Title",
    'attribute' 	= 'abc',
    'query_type'	= 'or',
    'type'		= 'select'
    'display' 		= 'all'
);

the_widget( 'YITH_WCAN_Navigation_Widget', $instance );
?>

As you can see is a bit more complex than you thought …