adding multiple parameters to an if statement

  • Oh, I’m not too sure how to explain this so I’ll just come out with it;

    If I can exclude a post ID that matches a wp_query, can I add a meta_value parameter too?

    My site displays a featured post on the index and beneath that 3 recent posts.

    Featured code looks like this

    $featured = new WP_Query();
$featured->query('showposts=1&meta_value=featured');
while($featured->have_posts()) : $featured->the_post();
$wp_query->in_the_loop = true;
$featured_ID = $post->ID;

    Once that’s done and it comes to the 3 recent posts this if statement makes sure that the featured_ID defined above isn’t displayed

    if ($post->ID != $featured_ID) { ?>

    This works fine, but say in the future I create another featured post within 2 posts of the last one, the older one will display in the recent posts since it no longer has the featured_ID, and I don’t want that.

    So using the if statement will it be possible to make sure that anything with meta_value=featured is also not displayed?

    Thanks in advance

Viewing 1 replies (of 1 total)
  • Thread Starter mrcairney

    (@mrcairney)

    I’ve been trying to get this to work and I think the way to achieve this is to exclude either a meta_key or value from the first query on the index page:

    <?php query_posts("showposts=4"); ?>
					<?php $first = true; ?>
					<?php if(have_posts()) : while(have_posts()) : the_post(); ?>
						<? if ($post->ID != $featured_ID) { ?>

    However, after reading the query codex, I can only add, not exclude.

    Example reading the codex, I’m pretty sure this should work:

    <?php query_posts("showposts=4&meta_compare= !=&meta_key=featured"); ?>

    But it doesn’t. The value for the featured key is ‘yes’ but even changing it to &meta_value=yes has no effect

    Can someone please shed some light on this, it’s driving me mad.

Viewing 1 replies (of 1 total)
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