Error during displaying results in a table from the database

It may be that your site is using a later version of PHP or a more-strict error-reporting level than your local machine.

What about this:

/ creation of my table
	<div class="my_box3">

            	<div class="box_title"><?php echo __("Title"); ?></div>
                <div class="box_content">
				<table border="1">
				<tr><th>A1</th><th>City</th><th>A2</th><th>A3</th><th>A4</th></tr>
				<?php 

// fill my table with recovered data
$ci=get_post_meta(get_the_ID(), 'CITY');

if (is_array($ci)) {
	$ci = array_filter($ci, , ARRAY_FILTER_USE_KEY);
	for($i=0;$i<count($ci);$i++) {
		?>
			<tr><td><?php echo load_by_id($ci[$i],"table","ID",$wpdb)->NAME;?>
		<?php
	}
}
?>
		</table>
	</div>
</div>

It’s using a test to make sure you’ve got an array first, which should eliminate the first warning, and then sets array_values to use the key, which I think you intended.

Thank you linux4me2,

I think the problem is with the loop for($i=0;$i<count($ci);$i++) because I have 5 columns in my table

There is the full code to filled my table with the data

<table border="1">
<tr><th>Country</th><th>City</th><th>University</th><th>Department</th><th>Year</th></tr>
<?php
$co=get_post_meta(get_the_ID(), 'COUNTRY');
$co=array_filter($co[0]);
$ci=get_post_meta(get_the_ID(), 'CITY');
$ci=array_filter($ci[0]);
$un=get_post_meta(get_the_ID(), 'UNIVERSITY');
$un=array_filter($un[0]);
$de=get_post_meta(get_the_ID(), 'DEPARTMENT');
$de=array_filter($de[0]);
$ye=get_post_meta(get_the_ID(), 'YEARU');
$ye=array_filter($ye[0]);
$ci=array_values($ci);
$co=array_values($co);
$un=array_values($un);
$de=array_values($de);
$ye=array_values($ye);
for($i=0;$i<count($co);$i++)
{?>
<tr><td><?php echo load_by_id($co[$i],"country","country_id",$wpdb)->COUNTRY_NAME;?></td><td><?php echo
load_by_id($ci[$i],"city","city_id",$wpdb)->CITY_NAME?></td><td><?php echo load_by_id($un[$i],"university_attributes","pk_i_id",$wpdb)->s_name?></td><td><?php echo load_by_id($de[$i],"department_attributes","pk_i_id",$wpdb)->s_name?></td><td><?php echo $ye[$i];?></td></tr>
<?php }?>
</table>

Any help will be appreciated, many thanks

I guess I’m a bit confused about what you’re trying to accomplish. Are you just trying to get the values for country, city, university, department, and year for one post and display them in a table, or for all posts with that meta data?

If you’re just trying to get them for one post, can’t you use something like this:

<table border="1">
	<tr><th>Country</th><th>City</th><th>University</th><th>Department</th><th>Year</th></tr>
	<?php
		$ID = get_the_ID();
		$fields = array('co'=>'COUNTRY', 'ci'=>'CITY', 'un'=>'UNIVERSITY', 'de'=>'DEPARTMENT', 'ye'=>'YEARU')
		foreach ($fields as $key=>$val) {
			$$key = get_post_meta($ID, $val, true);
		}
	?>
	<tr><td><?php echo $co; ?></td><td><?php echo $ci; ?></td><td><?php echo $un; ?></td><td><?php echo $de; ?></td><td><?php echo $ye; ?></td></tr>
</table>

I’m trying to get the values for one post but each post can have a multiple values of country, city, university, department, and year and when I leave some of them empty I get the error message

Warning: array_filter() expects parameter 1 to be array, string given
Warning: array_values() expects parameter 1 to be array, null given

in these lines (the empty column):
$line=array_filter($line[0]);
$line=array_values($line);

So I think that the problem is with the for loop because I’ve just declared one variable in parameters for($i=0;$i<count($co);$i++)

Can I replace this loop with another command to fill my table!

Many thanks linux4me2