Writing something in the loop after the first post

  • Hello everyone!!
    I’m having this problem that is suposed to be really easy and I don’t know why it’s not working… I’m trying to involve all the posts after the first one in a div to be hidden and collapsable…

    <?php query_posts( 'showposts=5' );?>
<?php $a = 0; ?>
<?php if ( have_posts() ) : while ( have_posts() ) : the_post(); ?>
	<?php $a = $a++; ?>
	<?php if ($a == 2) : ?>
		<span class="collapseomatic colomat-visited" id="id6158" alt="show more news" title="show more news">+</span>
		<span id="swap-id6158" style="display:none;">—</span>
		<div id="target-id6158" class="collapseomatic_content" style="display: none; ">
	<?php else: endif; ?>
	<?php the_content(); ?>
<?php endwhile; else: endif; ?>
<?php if ($a > 2){
	echo "</div>";
} ?>

    For that I created a variable $a that is going to be equal to the number of the current post in the loop, and when the post is the no 2 I make it write the button to hide and show the rest of the content and open the div that will hide the content…than, after all the loop has finished, I close the div.

    What is appearing on the page is the content as if there was no variable $a and if else to write the enclosure div.

    Can someone understand this? O.o
    Thanks in advance!

Viewing 4 replies - 1 through 4 (of 4 total)

  • I don’t!

    Instead of <?php $a = $a++; ?> try <?php $a++; ?>, not sure if it will fix your problem, but to my understanding the first $a is unnecessary, or maybe wrong even.

    Thread Starter MASSERRA

    (@masserra)

    Thanks for the reply! That’s the same, like doing a count, attributing the $a the value of the $a plus 1… But I tried and no… that doesn’t work… :/

    Thread Starter MASSERRA

    (@masserra)

    Ups…I was wrong..! My friend changed the template I was using on that page and when I tried the $a++ I thought it was not working… but the $a++ worked!! I thought it was the same as what I had… but now that it worked I just saw the error I was doing… $a++; is only the same as $a = $a + 1; like I sad in the last comment and, still, I didn’t notice… ??

Viewing 4 replies - 1 through 4 (of 4 total)
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