Custom Post Type Query Issue

Your first said:

But now I need it to pull in from my new custom post type called featured

then you used this example:

$wp_query = new WP_Query("post_type=property&post_status=publish&posts_per_page=5");

So is it post_type=featured or post_type=property?

Sorry, my bad.

That code was from the example site. On the site I’m having the issue however I am using post_type=featured.

wp_query = new WP_Query(“post_type=featured&post_status=publish&posts_per_page=5”);

Thank you!

Cheers,
Christopher

So ultimately, I need to replace:

query_posts("showposts=$featured_num&cat=".get_catId($featured_cat));

with

WP_Query("post_type=featured&post_status=publish&posts_per_page=5");

and add global $wp_query; above the if statement.

So instead of this:

if (get_option(‘wdg_use_pages’) == ‘false’) query_posts(“showposts=$featured_num&cat=”.get_catId($featured_cat));
else {

I would do this:

global $wp_query;

if (get_option(‘wdg_use_pages’) == ‘false’) wp_query = new WP_Query(“post_type=featured&post_status=publish&posts_per_page=5”);
else {

When I do that with debugging on I get, “Parse error: syntax error, unexpected ‘=’ ” on the line in question. I tried changing the = to == got a different error and then it started doing the slideshow but with every post in the CMS rather than just the specified post type.

Also in my functions file I have this:

/*Add Feature Custom Post Type*/
register_post_type(‘featured’, array(
‘label’ => __(‘Featured’),
‘singular_label’ => __(‘Feature’),
‘public’ => true,
‘show_ui’ => true, // UI in admin panel
‘_builtin’ => false, // It’s a custom post type, not built in!
‘_edit_link’ => ‘post.php?post=%d’,
‘capability_type’ => ‘post’,
‘hierarchical’ => false,
‘rewrite’ => array(“slug” => “featured”), // Permalinks format
‘supports’ => array(‘title’,’page-attributes’,’custom-fields’,’editor’,’thumbnail’,’excerpt’)
));

I’ll keep looking and experimenting on my own, but if anyone knows where I should devote my efforts please do!

Cheers,
Christopher

I totally figured it out. (Chris goes to buy himself a Starbucks coffee.

Two things:

First, thank you Michael again for noting in my post type I had =property. Because even though in my code I have =featured that got me thinking to look in my functions.php and I actually had the post type called “feature” without the d.

That was certainly an issue, and then I realized at some point I lost the $ in front of the wp_query. So with those two fixes it now works. Woot!

Cheers,
Christopher

PS – I heart WordPress

See what this returns:

<?php
//get specific post_types, display all published content for each of those types
$args=array(
  'name' => 'featured'
);
$output = 'objects'; // names or objects
$post_types=get_post_types($args,$output);
if ($post_types) {
  foreach ($post_types  as $post_type ) {
    $type = $post_type->name;
    $args=array(
      'post_type' => $type,
      'post_status' => 'publish',
      'posts_per_page' => -1,
      'caller_get_posts'=> 1
    );
    $my_query = null;
    $my_query = new WP_Query($args);
    if( $my_query->have_posts() ) {
      echo 'List of ' . $post_type->label;
      while ($my_query->have_posts()) : $my_query->the_post(); ?>
        <p><a href="<?php the_permalink() ?>" rel="bookmark" title="Permanent Link to <?php the_title_attribute(); ?>"><?php the_title(); ?></a></p>
        <?php
      endwhile;
    }
    wp_reset_query();
  }
}

?>

Thank you Michael. I actually figured out the issue. Posted my resolution above. But thank you for taking the time to diagnosis. Now I’m tackling meta boxes for custom post types. Wish me luck, I may be back!

Cheers,
Christopher

Okay missed you had posted back–that’s what I get for not refreshing.